Bangalore ODI: Rohit Sharma hits 209, India post 383/6
Records crumble in the seventh and last ODI between India and Australia in Bangalore, as India head towards a massive victory and on the verge of clinching the seven-match series 3-2. Rohit Sharma produced the ‘firecracker show’ on Diwali to power India in this series decider.
Rohit Sharma, the ‘Man of the Moment’ became the third batsman in the world after Sachin Tendulkar (200*) and Virender Sehwag (219) to score a double hundred in ODI cricket. He also broke the world record for maximum number of sixes in an innings with 16 sixes. The previous record was held by Shane Watson (15 sixes). India piled up 102 runs in last five overs.
Rohit Sharma also became the highest individual scorer against Australia in an innings. He made up for Virat Kohli’s loss through a run-out. Kohli (0) lost the chance to break Sir Vivian Richards’ quickest 5,000 runs in ODI. Sharma also completed his 1,000 runs this calendar year. Rohit had earlier scored 141 in Jaipur ODI and 79 in Nagpur ODI.
After being put by Australia into bat, India posted a mammoth total of 383/6, as Rohit Sharma scored 209 off 158 balls with 12 boundaries and 16 sixes. Shikhar Dhawan made 60, while Raina scored 28. Dhoni scored a quick-fire 62 off 38 balls. For Australia, Xavier Doherty took two wickets. The series is now levelled at 2-2. If India win today, they will take the series 3-2.